Question

14．如圖，已知y=ax+b和y=kx的圖象交于點P，根據(jù)圖象可得關(guān)于x、y的二元一次方程組$\left\{\begin{array}{l}{ax-y+b=0}\\{kx-y=0}\end{array}\right.$的解是$\left\{\begin{array}{l}{x=-4}\\{y=-2}\end{array}\right.$．

Answer 1

分析 根據(jù)函數(shù)圖象交點坐標(biāo)為兩函數(shù)解析式組成的方程組的解進(jìn)行解答．

解答 解：∵y=ax+b和y=kx的圖象交于點P（-4，-2），
∴方程組$\left\{\begin{array}{l}{ax-y+b=0}\\{kx-y=0}\end{array}\right.$的解是$\left\{\begin{array}{l}{x=-4}\\{y=-2}\end{array}\right.$．
故答案為$\left\{\begin{array}{l}{x=-4}\\{y=-2}\end{array}\right.$．

點評 本題考查了一次函數(shù)與二元一次方程（組）：函數(shù)圖象交點坐標(biāo)為兩函數(shù)解析式組成的方程組的解．