Question

3．已知函數(shù)y=ax+b與函數(shù)y=kx的圖象相交于點P，根據(jù)圖象，可得關(guān)于x、y的二元一次方程組$\left\{\begin{array}{l}{ax-y+b=0}\\{kx-y=0}\end{array}\right.$的解為$\left\{\begin{array}{l}{x=1}\\{y=-1}\end{array}\right.$．

Answer 1

分析 根據(jù)兩個一次函數(shù)組成的方程組的解就是兩函數(shù)圖象的交點可得二元一次方程組$\left\{\begin{array}{l}{ax-y+b=0}\\{kx-y=0}\end{array}\right.$的解為$\left\{\begin{array}{l}{x=1}\\{y=-1}\end{array}\right.$．

解答 解：∵函數(shù)y=ax+b與函數(shù)y=kx的圖象相交于點P（1，-1），
∴關(guān)于x、y的二元一次方程組$\left\{\begin{array}{l}{ax-y+b=0}\\{kx-y=0}\end{array}\right.$的解為$\left\{\begin{array}{l}{x=1}\\{y=-1}\end{array}\right.$，
故答案為：$\left\{\begin{array}{l}{x=1}\\{y=-1}\end{array}\right.$．

點評 此題主要考查了一次函數(shù)與二元一次方程，關(guān)鍵是掌握凡是函數(shù)圖象經(jīng)過的點必能滿足解析式．