分析:算式(1)可將式中的百分?jǐn)?shù)及分?jǐn)?shù)化為小數(shù)后,再根據(jù)乘法算式的性質(zhì)及乘法分配律進(jìn)行計(jì)算;
算式(2)可根據(jù)乘法交換律及乘法分配律計(jì)算;
算式(3)可將2003拆分為2002+1后再根據(jù)乘法分配律計(jì)算;
算式(4)根據(jù)乘法交換律及乘法分配律進(jìn)行計(jì)算.
解答:解:(1)
352.5×55%+60.5×5.5+42.5× =352.5×0.55+60.5×5.5+42.5×0.55,
=(352.5+42.5)×0.55+60.5×5.5,
=395×0.55+605×0.55,
=(395+605)×0.55,
=1000×0.55,
=550;
(2)
×+×=
×
+
×
,
=(
+
)×
,
=
×
,
=
;
(3)
2003× =(2002+1)×
,
=2002×
+
×1,
=2001+
,
=2001
;
(3)19×(
+)×25,
=
×25×19+
×19×25,
=38+75,
=113.
點(diǎn)評(píng):完成本類問題要注意分析式中數(shù)據(jù)的特點(diǎn)及內(nèi)在聯(lián)系,然后選擇合適的方法進(jìn)行計(jì)算.