考點:自然數(shù)的認識,奇數(shù)與偶數(shù)的初步認識,合數(shù)與質數(shù)
專題:整數(shù)的認識,數(shù)的整除
分析:在自然數(shù)中,最小的數(shù)是0,自然數(shù)中是2的倍數(shù)的數(shù)是偶數(shù),不是2的倍數(shù)的數(shù)是奇數(shù);除了1和本身外沒有沒有別的因數(shù)的數(shù)是質數(shù),除了1和它本身外還有別的因數(shù)的數(shù)為合數(shù).據(jù)此可知:最小的素數(shù)是2,最小的合數(shù)是4,最小的奇數(shù)是1,最小的偶數(shù)是0,既不是素數(shù)又不是合數(shù)的數(shù)是1;由此解答即可.
解答:
解:在自然數(shù)中,最小的數(shù)是0,最小的偶數(shù)是0,最小的奇數(shù)是1,最小的素數(shù)是2,最小的合數(shù)是4;
故答案為:0,0,1,2,4.
點評:奇數(shù)與偶數(shù)是以是否是2的倍數(shù)來區(qū)分的,質數(shù)與合數(shù)是以因數(shù)的多少來區(qū)分的.