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(1+
1
7
+
1
9
+
1
11
)
×(
1
7
+
1
9
+
1
11
+
1
21
)
-(1+
1
7
+
1
9
+
1
11
+
1
21
)
×(
1
7
+
1
9
+
1
11
)
分析:根據(jù)乘法分配律對原式進(jìn)行變形解答.
解答:解:(1+
1
7
+
1
9
+
1
11
)
×(
1
7
+
1
9
+
1
11
+
1
21
)
-(1+
1
7
+
1
9
+
1
11
+
1
21
)
×(
1
7
+
1
9
+
1
11
)

=[1+(
1
7
+
1
9
+
1
11
)]×(
1
7
+
1
9
+
1
11
+
1
21
)
-[(1+(
1
7
+
1
9
+
1
11
+
1
21
)
(
1
7
+
1
9
+
1
11
)

=(
1
7
+
1
9
+
1
11
+
1
21
)
+(
1
7
+
1
9
+
1
11
)×(
1
7
+
1
9
+
1
11
+
1
21
)
-(
1
7
+
1
9
+
1
11
)
-(
1
7
+
1
9
+
1
11
+
1
21
)
×(
1
7
+
1
9
+
1
11
)
,
(
1
7
+
1
9
+
1
11
+
1
21
)
-(
1
7
+
1
9
+
1
11
)
,
=
1
21
點(diǎn)評:本題的關(guān)鍵是根據(jù)乘法分配律對題變形,再化簡進(jìn)行計(jì)算.
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