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解:(1)去超市購買所需費用 即··········································································································· 1分 去超市購買所需費用 即········································································································· 2分 當時.即 當時.即 當時.即 ·························································································································· 4分 綜上所述:當時.去超市購買更合算,當時.去超市或超市購買一樣,當時.去超市購買更合算.···················································································································· 5分 (2)當時.即購買10副球拍應(yīng)配120個乒乓球 若只去超市購買的費用為: (元)············································································· 6分 若在超市購買10副球拍.去超市購買余下的乒乓球的費用為: (元)··············································································· 7分 最佳方案為:只在超市購買10副球拍.同時獲得送30個乒乓球.然后去超市按九折購買90個乒乓球. 8分 查看更多

 

題目列表(包括答案和解析)

16、問題背景:
A、B兩家超市都有某種品牌的乒乓球拍和乒乓球出售,且每副球拍的標價都為50元,每個乒乓球的標價都為2元.現(xiàn)兩家超市正在促銷,A超市所有商品均打九折銷售,而B超市買一副乒乓球拍送4個乒乓球.若僅考慮購買球拍和乒乓球的費用.
(1)如果只在某一家超市購一副乒乓球拍和10個乒乓球,問去A超市還是B超市買更合算?
遷移運用:
(2)某乒乓球訓練館準備購買n副該種品牌的乒乓球拍,每副球拍配k(k≥4)個乒乓球.如果只在某一家超市購買,問去A超市還是B超市買更合算?
拓展延伸:
(3)若乒乓球訓練館準備購買n副該種品牌的乒乓球拍,每副球拍配20個乒乓球.請通過計算設(shè)計出最省錢的購買方案.

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列方程(組)解應(yīng)用題:
張欣的媽媽用面值為100元的購物券去超市購物.她們想購買的兩種商品分別是:每袋8元的洗衣粉和每袋15元的巧克力,且打算兩種商品共買9袋.請問她們應(yīng)該購買兩種商品各幾袋,才能使購物券恰好用完.

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列方程(組)解應(yīng)用題
張欣的媽媽用面值為100元的購物券去超市購物。她們想購買的兩種商品分別是:每袋8元的洗衣粉和每袋15元的巧克力,且打算兩種商品共買9袋。請問她們應(yīng)該購買兩種商品各幾袋,才能使購物券恰好用完?

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列方程(組)解應(yīng)用題

張欣的媽媽用面值為100元的購物券去超市購物。她們想購買的兩種商品分別是:每袋8元的洗衣粉和每袋15元的巧克力,且打算兩種商品共買9袋。請問她們應(yīng)該購買兩種商品各幾袋,才能使購物券恰好用完?

 

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列方程(組)解應(yīng)用題:
張欣的媽媽用面值為100元的購物券去超市購物.她們想購買的兩種商品分別是:每袋8元的洗衣粉和每袋15元的巧克力,且打算兩種商品共買9袋.請問她們應(yīng)該購買兩種商品各幾袋,才能使購物券恰好用完.

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