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1.已知全集I=.A=.B=.則CI()= 查看更多

 

題目列表(包括答案和解析)

已知全集I={-2,-1,0,1,2,3,4,5},集合A={-1,0,1,2,3},B={-2,0,2},則CI(A∪B)等于( )
A.{-2,-1,0,1,3}
B.{0,2}
C.{-2,-1,1,3,4,5}
D.{4,5}

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已知U為全集,A,B,I都是U的子集,且A⊆I,B⊆I,則CI(A∩B)=( 。

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已知U為全集,A,B,I都是U的子集,且A⊆I,B⊆I,則CI(A∩B)=( 。
A.{x∈U|x∉A且x∉B}B.{x∈U|x∉A或x∉B}
C.{x∈I|x∉A且x∉B}D.{x∈I|x∉A或x∉B}

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已知U為全集,A,B,I都是U的子集,且A⊆I,B⊆I,則CI(A∩B)=( )
A.{x∈U|x∉A且x∉B}
B.{x∈U|x∉A或x∉B}
C.{x∈I|x∉A且x∉B}
D.{x∈I|x∉A或x∉B}

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已知U為全集,A,B,I都是U的子集,且A⊆I,B⊆I,則CI(A∩B)=( )
A.{x∈U|x∉A且x∉B}
B.{x∈U|x∉A或x∉B}
C.{x∈I|x∉A且x∉B}
D.{x∈I|x∉A或x∉B}

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一.選擇題

1―5  CBABA   6―10  CADDA

二.填空題

11.       12.()       13.2          14.         15.

16.(1,4)

三.解答題

數(shù)學(xué)理數(shù)學(xué)理17,解:①         =2(1,0)                      (2分)             

        ?,                                        (4分)

?

        cos              =

 

        由,  ,    即B=              (6分)

                                               (7分)

                                                        (9分)

,                                                         (11分)

的取值范圍是(,1                                                      (13分)

18.解:①設(shè)雙曲線方程為:  ()                                 (1分)

由橢圓,求得兩焦點,                                           (3分)

,又為一條漸近線

, 解得:                                                     (5分)

                                                    (6分)

②設(shè),則                                                      (7分)

      

?                             (9分)

,  ?              (10分)

                                                (11分)

  ?

?                                        (13分)

    1. <var id="r4mr4"></var>

            <u id="r4mr4"></u>

              單減區(qū)間為[]        (6分)

             

            ②(i)當(dāng)                                                      (8分)

            (ii)當(dāng),

            ,  (),,

            則有                                                                     (10分)

            ,

                                                           (11分)

              在(0,1]上單調(diào)遞減                     (12分)

                                                             (13分)

            20.解:①       

                                                                    (2分)

            從而數(shù)列{}是首項為1,公差為C的等差數(shù)列

              即                                (4分)

             

               即………………※              (6分)

            當(dāng)n=1時,由※得:c<0                                                    (7分)

            當(dāng)n=2時,由※得:                                                 (8分)

            當(dāng)n=3時,由※得:                                                 (9分)

            當(dāng)

                (

                                                      (11分)

                                     (12分)

            綜上分析可知,滿足條件的實數(shù)c不存在.                                    (13分)

            21.解:①設(shè)過A作拋物線的切線斜率為K,則切線方程:

                                                                            (2分)

                即

                                                                                                               (3分)

            ②設(shè)   又

                 

                                                                     (4分)

            同理可得 

                                                            (5分)

            又兩切點交于 

                                           (6分)

            ③由  可得:

             

                                                            (8分)

                              (9分)

             

            當(dāng) 

            當(dāng) 

                                                                 (11分)

            當(dāng)且僅當(dāng),取 “=”,此時

                                                   (12分)

            22.①證明:由   

              即證

              ()                                    (1分)

            當(dāng)  

                  即:                          (3分)

              ()    

            當(dāng)   

               

                                                                     (6分)

            ②由      

            數(shù)列

                                                          (8分)

            由①可知, 

                                (10分)

            由錯位相減法得:                                       (11分)

                                                (12分)