Question

logab2logb2a=

1

．

Answer 1

分析：logab2logb2a═

lgb2

lga

×

lga

lgb2

，由此能求出其結(jié)果．

解答：解：logab2logb2a
=

lgb2

lga

×

lga

lgb2

=1．
故答案為：1．

點(diǎn)評：本題考查對數(shù)的運(yùn)算性質(zhì)，解題時(shí)要認(rèn)真審題，注意對數(shù)運(yùn)算法則的靈活運(yùn)用．