Question

16．|1-$\sqrt{2}$|=$\sqrt{2}$-1，$\root{3}{-27}$-$\sqrt{1}$=-4，$\frac{\sqrt{3}-\sqrt{12}}{\sqrt{3}}$=-1．

Answer 1

分析 結(jié)合題目分別進(jìn)行絕對(duì)值的化簡(jiǎn)、開(kāi)立方、二次根式的化簡(jiǎn)等運(yùn)算．

解答 解：|1-$\sqrt{2}$|=$\sqrt{2}$-1，

$\root{3}{-27}$-$\sqrt{1}$
=-3-1
=-4；

$\frac{\sqrt{3}-\sqrt{12}}{\sqrt{3}}$
=1-2
=-1．
故答案為：$\sqrt{2}$-1；-4；-1．

點(diǎn)評(píng) 本題考查了實(shí)數(shù)的運(yùn)算，解答本題的關(guān)鍵是掌握絕對(duì)值的化簡(jiǎn)、開(kāi)立方、二次根式的化簡(jiǎn)等運(yùn)算法則．