Question

多項(xiàng)式-8m²n³+10m³n²+2m²n²被-2m²n²除，所得的商為

4n-5m-1

．

Answer 1

分析：根據(jù)已知得出（-8m²n³+10m³n²+2m²n²）÷（-2m²n²），再利用多項(xiàng)式除以單項(xiàng)式，先把多項(xiàng)式的每一項(xiàng)都分別除以這個(gè)單項(xiàng)式，然后再把所得的商相加計(jì)算后即可選取答案．

解答：解：（-8m²n³+10m³n²+2m²n²）÷（-2m²n²），
=-8m²n³÷（-2m²n²）+10m³n²÷（-2m²n²）+2m²n²÷（-2m²n²），
=4n-5m-1．
故答案為：4n-5m-1．

點(diǎn)評(píng)：本題主要考查多項(xiàng)式除單項(xiàng)式，熟練掌握運(yùn)算法則得出-8m²n³+10m³n²+2m²n²被-2m²n²除的運(yùn)算式子是解題的關(guān)鍵．