Question

22、已知：如圖，△ABC≌△DEF，BC∥EF，∠A=∠D，BC=EF，則另外兩組對(duì)應(yīng)邊是

AB和DF，AC和DE

，另外兩組對(duì)應(yīng)角是

∠ACB和∠DEF，∠B和∠F

．

Answer 1

分析：根據(jù)兩直線(xiàn)平行，內(nèi)錯(cuò)角相等可得∠ACB=∠DEF，又∠A=∠D，所以對(duì)應(yīng)角確定，再根據(jù)對(duì)應(yīng)角所對(duì)的邊是對(duì)應(yīng)邊寫(xiě)出即可．

解答：解：∵BC∥EF，∴∠ACB=∠DEF，
又∵∠A=∠D，
∴∠A和∠D，∠ACB和∠DEF，∠B和∠F是對(duì)應(yīng)角；
因?yàn)閷?duì)應(yīng)角所對(duì)的邊是對(duì)應(yīng)邊，
所以AB和DF，AC和DE，BC和EF是對(duì)應(yīng)邊．
故應(yīng)填A(yù)B和DF，AC和DE；∠ACB和∠DEF，∠B和∠F．

點(diǎn)評(píng)：本題主要考查全等三角形的性質(zhì)及對(duì)應(yīng)邊與對(duì)應(yīng)角的找法，先確定出對(duì)應(yīng)角或?qū)��?yīng)邊，再根據(jù)對(duì)應(yīng)角所對(duì)的邊是對(duì)應(yīng)邊，對(duì)應(yīng)邊所對(duì)的角是對(duì)應(yīng)角確定．