500g溶質(zhì)質(zhì)量分數(shù)為10%的葡萄糖溶液里,含葡萄糖________g,含有水________g;若從中取走250g,剩余溶液中含有葡萄糖________g,含水________g,溶質(zhì)的質(zhì)量分數(shù)為________.
50 450 25 225 10%
分析:利用溶質(zhì)質(zhì)量=溶液質(zhì)量×溶質(zhì)的質(zhì)量分數(shù),可根據(jù)溶液的質(zhì)量和溶質(zhì)的質(zhì)量分數(shù)計算配制溶液所需要的溶質(zhì)的質(zhì)量;再根據(jù)溶劑質(zhì)量=溶液質(zhì)量-溶質(zhì)質(zhì)量即可求得蒸餾水的質(zhì)量;根據(jù)溶液具有均一性進行分析解答.
解答:500g溶質(zhì)質(zhì)量分數(shù)為10%的葡萄糖溶液里,含葡萄糖的質(zhì)量為500g×10%=50g,含水的質(zhì)量為500g-50g=450g.
若從中取走250g,剩余溶液中含有葡萄糖和水的質(zhì)量均為原溶液的一半,則剩余溶液中含有葡萄糖50g÷2=25g,含水的質(zhì)量為450g÷2=225g;溶液具有均一性,
溶質(zhì)的質(zhì)量分數(shù)仍為10%.
故答案為:50;450;25;225;10%.
點評:本題難度不大,掌握溶質(zhì)質(zhì)量分數(shù)的有關計算并能靈活運用是正確解答本題的關鍵.