Question

16g Fe₂O₃與184g稀H₂SO₄恰好完全反應，求所得Fe₂(SO₄)₃溶液的溶質(zhì)質(zhì)量分數(shù)？

Answer 1

（3分）解：設反應生成的Fe₂(SO₄)₃的質(zhì)量為x
Fe₂O₃+3H₂SO₄===Fe₂(SO₄)₃+3H₂O                            （1分）   
160             400
16g              x     
 
x=40g                                                 （1分）   
溶質(zhì)的質(zhì)量分數(shù)為：               （1分）   
答：所得溶液的溶質(zhì)質(zhì)量分數(shù)為20%。