Question

20毫升水倒入10毫升質(zhì)量分?jǐn)?shù)為98%的濃硫酸（密度為1.84g/mL）中攪拌均勻，所得溶液溶質(zhì)質(zhì)量分?jǐn)?shù)計(jì)算式正確的是（　�。�

• A、

  10×1.84×98%

  10×1.84+20×1

• B、

  10×98%

  10+20

  ×100%
• C、

  10×1.84×98%

  10×1.84×98%+20×1

  ×100%
• D、

  10×1.84

  10×1.84+20×1

  ×100%

Answer 1

考點(diǎn)：有關(guān)溶質(zhì)質(zhì)量分?jǐn)?shù)的簡(jiǎn)單計(jì)算

專題：溶液的組成及溶質(zhì)質(zhì)量分?jǐn)?shù)的計(jì)算

分析：根據(jù)溶液稀釋前后，溶質(zhì)的質(zhì)量不變，結(jié)合題意、溶質(zhì)質(zhì)量=溶液質(zhì)量×溶質(zhì)的質(zhì)量分?jǐn)?shù)，進(jìn)行分析解答．

解答：解：20毫升水倒入10毫升質(zhì)量分?jǐn)?shù)為98%的濃硫酸（密度為1.84g/mL）中攪拌均勻，所得溶液溶質(zhì)質(zhì)量分?jǐn)?shù)計(jì)算式為

1.84g/mL×10mL×98%

1.84g/mL×10mL+1g/ml×20mL

×100%=

1.84×10×98%

1.84×10+20×1

．
故選：A．

點(diǎn)評(píng)：本題難度不大，掌握溶液稀釋前后溶質(zhì)的質(zhì)量不變、溶質(zhì)質(zhì)量=溶液質(zhì)量×溶質(zhì)的質(zhì)量分?jǐn)?shù)是正確解答本題的關(guān)鍵．